Remainder Theorem INB 90 1/14/13

INB 81 – ACT Geometry Review:

#1, #2

#1, #2

#3, #4

#3, #4

 

 

 

 

 

Monday 1/14/13 In Class Notes / Examples:

Friday we “discovered” that we could substitude “a” into our polynomial and the result would be the remainder if we divided by (x-a).

Today, we’re answering the question “When we use  Remainder Theorem, what is this really telling us?”

INB page 90 “More Remainder Theorem”

We graphed the given polynomial as a function in our graphing calculators.  Noted the x-intercepts. "Created" factors from our x-intercepts, then graphed our factors to see the graphed resulted in the same thing.

We graphed the given polynomial as a function in our graphing calculators. Noted the x-intercepts. “Created” factors from our x-intercepts, then graphed our factors to see the graphed resulted in the same thing.

 
We used the remainder theorem to show that (x+5) was indeed a factor!

We used the remainder theorem to show that (x+5) was indeed a factor!

Again, we used the Remainder Theorem to show (x-1) was NOT a factor.  Students already noted it was not an x-intercept on the graph.

Assignment/Practice due Tuesday:  

remaindertheorempractice11413

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